42=(x+3)(2x+8)/2

Solution for 42=(x+3)(2x+8)/2 equation:

42=(x+3)(2x+8)/2

We move all terms to the left:

42-((x+3)(2x+8)/2)=0

We multiply parentheses ..

-((+2x^2+8x+6x+24)/2)+42=0

We multiply all the terms by the denominator


-((+2x^2+8x+6x+24)+42*2)=0


We calculate terms in parentheses: -((+2x^2+8x+6x+24)+42*2), so:

(+2x^2+8x+6x+24)+42*2

We add all the numbers together, and all the variables

(+2x^2+8x+6x+24)+84

We get rid of parentheses

2x^2+8x+6x+24+84

We add all the numbers together, and all the variables

2x^2+14x+108

Back to the equation:

-(2x^2+14x+108)


We get rid of parentheses

-2x^2-14x-108=0

a = -2; b = -14; c = -108;
Δ = b2-4ac
Δ = -142-4·(-2)·(-108)
Δ = -668
Delta is less than zero, so there is no solution for the equation