42=(x+3)+(2x)

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Solution for 42=(x+3)+(2x) equation:



42=(x+3)+(2x)
We move all terms to the left:
42-((x+3)+(2x))=0
We calculate terms in parentheses: -((x+3)+2x), so:
(x+3)+2x
We add all the numbers together, and all the variables
2x+(x+3)
We get rid of parentheses
2x+x+3
We add all the numbers together, and all the variables
3x+3
Back to the equation:
-(3x+3)
We get rid of parentheses
-3x-3+42=0
We add all the numbers together, and all the variables
-3x+39=0
We move all terms containing x to the left, all other terms to the right
-3x=-39
x=-39/-3
x=+13

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