42=(x/(40+2x))

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Solution for 42=(x/(40+2x)) equation: 



42=(x/(40+2x))

We move all terms to the left:

42-((x/(40+2x)))=0



Domain of the equation: (40+2x)))!=0

We move all terms containing x to the left, all other terms to the right

2x))!=-40

x!=-40/1

x!=-40

x∈R



We add all the numbers together, and all the variables

-((x/(2x+40)))+42=0

We multiply all the terms by the denominator


-((x+42*(2x+40)))=0



We calculate terms in parentheses: -((x+42*(2x+40))), so:

(x+42*(2x+40))



We calculate terms in parentheses: +(x+42*(2x+40)), so:

x+42*(2x+40)

We multiply parentheses

x+84x+1680

We add all the numbers together, and all the variables

85x+1680

Back to the equation:

+(85x+1680)



We get rid of parentheses

85x+1680

Back to the equation:

-(85x+1680)



We get rid of parentheses

-85x-1680=0

We move all terms containing x to the left, all other terms to the right

-85x=1680

x=1680/-85

x=-19+13/17

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