42=-2(22-b)+3(b-3)

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Solution for 42=-2(22-b)+3(b-3) equation: 



42=-2(22-b)+3(b-3)

We move all terms to the left:

42-(-2(22-b)+3(b-3))=0

We add all the numbers together, and all the variables

-(-2(-1b+22)+3(b-3))+42=0



We calculate terms in parentheses: -(-2(-1b+22)+3(b-3)), so:

-2(-1b+22)+3(b-3)

We multiply parentheses

2b+3b-44-9

We add all the numbers together, and all the variables

5b-53

Back to the equation:

-(5b-53)



We get rid of parentheses

-5b+53+42=0

We add all the numbers together, and all the variables

-5b+95=0

We move all terms containing b to the left, all other terms to the right

-5b=-95

b=-95/-5

b=+19

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