42=-8(3-k)+6(k-3)

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Solution for 42=-8(3-k)+6(k-3) equation: 



42=-8(3-k)+6(k-3)

We move all terms to the left:

42-(-8(3-k)+6(k-3))=0

We add all the numbers together, and all the variables

-(-8(-1k+3)+6(k-3))+42=0



We calculate terms in parentheses: -(-8(-1k+3)+6(k-3)), so:

-8(-1k+3)+6(k-3)

We multiply parentheses

8k+6k-24-18

We add all the numbers together, and all the variables

14k-42

Back to the equation:

-(14k-42)



We get rid of parentheses

-14k+42+42=0

We add all the numbers together, and all the variables

-14k+84=0

We move all terms containing k to the left, all other terms to the right

-14k=-84

k=-84/-14

k=+6

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