42=1/2(x+3)(2x+8)

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Solution for 42=1/2(x+3)(2x+8) equation: 



42=1/2(x+3)(2x+8)

We move all terms to the left:

42-(1/2(x+3)(2x+8))=0



Domain of the equation: 2(x+3)(2x+8))!=0

x∈R



We multiply parentheses ..

-(1/2(+2x^2+8x+6x+24))+42=0

We multiply all the terms by the denominator


-(1+42*2(+2x^2+8x+6x+24))=0



We calculate terms in parentheses: -(1+42*2(+2x^2+8x+6x+24)), so:

1+42*2(+2x^2+8x+6x+24)

determiningTheFunctionDomain
42*2(+2x^2+8x+6x+24)+1

Wy multiply elements

84x(++1

We use the square of the difference formula

84x(+1

Back to the equation:

-(84x(+1)



We add all the numbers together, and all the variables

-(84x1=0

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