42=1/2+(2x+8)(x+3)

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Solution for 42=1/2+(2x+8)(x+3) equation: 



42=1/2+(2x+8)(x+3)

We move all terms to the left:

42-(1/2+(2x+8)(x+3))=0



Domain of the equation: 2+(2x+8)(x+3))!=0

We move all terms containing x to the left, all other terms to the right

(2x+8)(x+3))!=-2

x∈R



We multiply parentheses ..

-(1/2+(+2x^2+6x+8x+24))+42=0

We multiply all the terms by the denominator


-(1+42*2+(+2x^2+6x+8x+24))=0



We calculate terms in parentheses: -(1+42*2+(+2x^2+6x+8x+24)), so:

1+42*2+(+2x^2+6x+8x+24)

determiningTheFunctionDomain
(+2x^2+6x+8x+24)+1+42*2

We add all the numbers together, and all the variables

(+2x^2+6x+8x+24)+85

We get rid of parentheses

2x^2+6x+8x+24+85

We add all the numbers together, and all the variables

2x^2+14x+109

Back to the equation:

-(2x^2+14x+109)



We get rid of parentheses

-2x^2-14x-109=0

a = -2; b = -14; c = -109;
Δ = b2-4ac
Δ = -142-4·(-2)·(-109)
Δ = -676
Delta is less than zero, so there is no solution for the equation

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