42=2(1+4v)+2v

Simple and best practice solution for 42=2(1+4v)+2v equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.

If it's not what You are looking for type in the equation solver your own equation and let us solve it.

Solution for 42=2(1+4v)+2v equation: 



42=2(1+4v)+2v

We move all terms to the left:

42-(2(1+4v)+2v)=0

We add all the numbers together, and all the variables

-(2(4v+1)+2v)+42=0



We calculate terms in parentheses: -(2(4v+1)+2v), so:

2(4v+1)+2v

We add all the numbers together, and all the variables

2v+2(4v+1)

We multiply parentheses

2v+8v+2

We add all the numbers together, and all the variables

10v+2

Back to the equation:

-(10v+2)



We get rid of parentheses

-10v-2+42=0

We add all the numbers together, and all the variables

-10v+40=0

We move all terms containing v to the left, all other terms to the right

-10v=-40

v=-40/-10

v=+4

See similar equations:

| -10z=-90 | | -t+7=-7 | | 18=r-51 | | 11h-7h=16 | | 4p+6p-8=12 | | 14x–11x+25=37 | | j+491=596 | | 18=r51 | | w/43=1 | | 0.666=(1+x)^6 | | 99=f+66 | | x+11/13=2 | | w/13.5=9,7 | | -1=-1+n/6 | | 3=h-24 | | -6.8=1.7r | | 3(b-+5b=44 | | 3x(11x)=-66 | | 3(x+4)^1/2=15 | | 57=3v-33 | | 44=v-9 | | z+13=65 | | q/5=-6 | | 7c-5c=18 | | 7.8x=82.5 | | h+38=79 | | 7(2m-8)=25 | | 6k^2+2k-4=-4 | | y^2(y-4)^2=0 | | b-(-35)=72 | | 1/6(y+42)–15=-3 | | p-92/2=3 |

Equations solver categories