42=2(12+3y)

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Solution for 42=2(12+3y) equation: 



42=2(12+3y)

We move all terms to the left:

42-(2(12+3y))=0

We add all the numbers together, and all the variables

-(2(3y+12))+42=0



We calculate terms in parentheses: -(2(3y+12)), so:

2(3y+12)

We multiply parentheses

6y+24

Back to the equation:

-(6y+24)



We get rid of parentheses

-6y-24+42=0

We add all the numbers together, and all the variables

-6y+18=0

We move all terms containing y to the left, all other terms to the right

-6y=-18

y=-18/-6

y=+3

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