42=2(3+2x)+2(x)

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Solution for 42=2(3+2x)+2(x) equation: 



42=2(3+2x)+2(x)

We move all terms to the left:

42-(2(3+2x)+2(x))=0

We add all the numbers together, and all the variables

-(2(2x+3)+2x)+42=0



We calculate terms in parentheses: -(2(2x+3)+2x), so:

2(2x+3)+2x

We add all the numbers together, and all the variables

2x+2(2x+3)

We multiply parentheses

2x+4x+6

We add all the numbers together, and all the variables

6x+6

Back to the equation:

-(6x+6)



We get rid of parentheses

-6x-6+42=0

We add all the numbers together, and all the variables

-6x+36=0

We move all terms containing x to the left, all other terms to the right

-6x=-36

x=-36/-6

x=+6

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