42=2(3x+1)+2(x-4)

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Solution for 42=2(3x+1)+2(x-4) equation: 



42=2(3x+1)+2(x-4)

We move all terms to the left:

42-(2(3x+1)+2(x-4))=0



We calculate terms in parentheses: -(2(3x+1)+2(x-4)), so:

2(3x+1)+2(x-4)

We multiply parentheses

6x+2x+2-8

We add all the numbers together, and all the variables

8x-6

Back to the equation:

-(8x-6)



We get rid of parentheses

-8x+6+42=0

We add all the numbers together, and all the variables

-8x+48=0

We move all terms containing x to the left, all other terms to the right

-8x=-48

x=-48/-8

x=+6

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