42=2(m+4)-m

Solution for 42=2(m+4)-m equation:

42=2(m+4)-m

We move all terms to the left:

42-(2(m+4)-m)=0


We calculate terms in parentheses: -(2(m+4)-m), so:

2(m+4)-m

We add all the numbers together, and all the variables

-1m+2(m+4)

We multiply parentheses

-1m+2m+8

We add all the numbers together, and all the variables

m+8

Back to the equation:

-(m+8)


We get rid of parentheses

-m-8+42=0

We add all the numbers together, and all the variables

-1m+34=0

We move all terms containing m to the left, all other terms to the right

-m=-34

m=-34/-1

m=+34