42=2f-6(2f+3)

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Solution for 42=2f-6(2f+3) equation: 



42=2f-6(2f+3)

We move all terms to the left:

42-(2f-6(2f+3))=0



We calculate terms in parentheses: -(2f-6(2f+3)), so:

2f-6(2f+3)

We multiply parentheses

2f-12f-18

We add all the numbers together, and all the variables

-10f-18

Back to the equation:

-(-10f-18)



We get rid of parentheses

10f+18+42=0

We add all the numbers together, and all the variables

10f+60=0

We move all terms containing f to the left, all other terms to the right

10f=-60

f=-60/10

f=-6

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