42=2x+3(3x+3)

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Solution for 42=2x+3(3x+3) equation: 



42=2x+3(3x+3)

We move all terms to the left:

42-(2x+3(3x+3))=0



We calculate terms in parentheses: -(2x+3(3x+3)), so:

2x+3(3x+3)

We multiply parentheses

2x+9x+9

We add all the numbers together, and all the variables

11x+9

Back to the equation:

-(11x+9)



We get rid of parentheses

-11x-9+42=0

We add all the numbers together, and all the variables

-11x+33=0

We move all terms containing x to the left, all other terms to the right

-11x=-33

x=-33/-11

x=+3

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