42=3(2-3b)

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Solution for 42=3(2-3b) equation:



42=3(2-3b)
We move all terms to the left:
42-(3(2-3b))=0
We add all the numbers together, and all the variables
-(3(-3b+2))+42=0
We calculate terms in parentheses: -(3(-3b+2)), so:
3(-3b+2)
We multiply parentheses
-9b+6
Back to the equation:
-(-9b+6)
We get rid of parentheses
9b-6+42=0
We add all the numbers together, and all the variables
9b+36=0
We move all terms containing b to the left, all other terms to the right
9b=-36
b=-36/9
b=-4

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