42=3(k-2)

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Solution for 42=3(k-2) equation: 



42=3(k-2)

We move all terms to the left:

42-(3(k-2))=0



We calculate terms in parentheses: -(3(k-2)), so:

3(k-2)

We multiply parentheses

3k-6

Back to the equation:

-(3k-6)



We get rid of parentheses

-3k+6+42=0

We add all the numbers together, and all the variables

-3k+48=0

We move all terms containing k to the left, all other terms to the right

-3k=-48

k=-48/-3

k=+16

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