42=3x-4(-x-12)

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Solution for 42=3x-4(-x-12) equation: 



42=3x-4(-x-12)

We move all terms to the left:

42-(3x-4(-x-12))=0

We add all the numbers together, and all the variables

-(3x-4(-1x-12))+42=0



We calculate terms in parentheses: -(3x-4(-1x-12)), so:

3x-4(-1x-12)

We multiply parentheses

3x+4x+48

We add all the numbers together, and all the variables

7x+48

Back to the equation:

-(7x+48)



We get rid of parentheses

-7x-48+42=0

We add all the numbers together, and all the variables

-7x-6=0

We move all terms containing x to the left, all other terms to the right

-7x=6

x=6/-7

x=-6/7

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