42=4/9(3.24)d

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Solution for 42=4/9(3.24)d equation: 



42=4/9(3.24)d

We move all terms to the left:

42-(4/9(3.24)d)=0



Domain of the equation: 9(3.24)d)!=0

d∈R



We multiply all the terms by the denominator


-(4+42*9(3.24)d)=0



We calculate terms in parentheses: -(4+42*9(3.24)d), so:

4+42*9(3.24)d

determiningTheFunctionDomain
42*9(3.24)d+4

Wy multiply elements

378d(3+4

Back to the equation:

-(378d(3+4)



We add all the numbers together, and all the variables

-(378d7=0

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