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42=5/9(x-32)
We move all terms to the left:
42-(5/9(x-32))=0
Domain of the equation: 9(x-32))!=0We multiply all the terms by the denominator
x∈R
-(5+42*9(x-32))=0
We calculate terms in parentheses: -(5+42*9(x-32)), so:
5+42*9(x-32)
determiningTheFunctionDomain 42*9(x-32)+5
Wy multiply elements
378x(x+5
Back to the equation:
-(378x(x+5)
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