42x2=168

Solution for 42x2=168 equation:

42x^2=168

We move all terms to the left:

42x^2-(168)=0

a = 42; b = 0; c = -168;
Δ = b2-4ac
Δ = 02-4·42·(-168)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-168}{2*42}=\frac{-168}{84}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+168}{2*42}=\frac{168}{84}
=2
$