43(g-7)=2(10+g)

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Solution for 43(g-7)=2(10+g) equation: 



43(g-7)=2(10+g)

We move all terms to the left:

43(g-7)-(2(10+g))=0

We add all the numbers together, and all the variables

43(g-7)-(2(g+10))=0

We multiply parentheses

43g-(2(g+10))-301=0



We calculate terms in parentheses: -(2(g+10)), so:

2(g+10)

We multiply parentheses

2g+20

Back to the equation:

-(2g+20)



We get rid of parentheses

43g-2g-20-301=0

We add all the numbers together, and all the variables

41g-321=0

We move all terms containing g to the left, all other terms to the right

41g=321

g=321/41

g=7+34/41

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