43+(3x+18)+(6x-16)=180

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Solution for 43+(3x+18)+(6x-16)=180 equation: 



43+(3x+18)+(6x-16)=180

We move all terms to the left:

43+(3x+18)+(6x-16)-(180)=0

We add all the numbers together, and all the variables

(3x+18)+(6x-16)-137=0

We get rid of parentheses

3x+6x+18-16-137=0

We add all the numbers together, and all the variables

9x-135=0

We move all terms containing x to the left, all other terms to the right

9x=135

x=135/9

x=15

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