43/12w+1814=25/6w+1744

Solution for 43/12w+1814=25/6w+1744 equation:

43/12w+1814=25/6w+1744

We move all terms to the left:

43/12w+1814-(25/6w+1744)=0


Domain of the equation: 12w!=0

w!=0/12

w!=0

w∈R



Domain of the equation: 6w+1744)!=0

w∈R


We get rid of parentheses

43/12w-25/6w-1744+1814=0

We calculate fractions


258w/72w^2+(-300w)/72w^2-1744+1814=0

We add all the numbers together, and all the variables

258w/72w^2+(-300w)/72w^2+70=0

We multiply all the terms by the denominator


258w+(-300w)+70*72w^2=0

Wy multiply elements

5040w^2+258w+(-300w)=0

We get rid of parentheses

5040w^2+258w-300w=0

We add all the numbers together, and all the variables

5040w^2-42w=0

a = 5040; b = -42; c = 0;
Δ = b2-4ac
Δ = -422-4·5040·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-42}{2*5040}=\frac{0}{10080}
=0
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+42}{2*5040}=\frac{84}{10080}
=1/120
$