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432/36x=x
We move all terms to the left:
432/36x-(x)=0
Domain of the equation: 36x!=0We add all the numbers together, and all the variables
x!=0/36
x!=0
x∈R
-1x+432/36x=0
We multiply all the terms by the denominator
-1x*36x+432=0
Wy multiply elements
-36x^2+432=0
a = -36; b = 0; c = +432;
Δ = b2-4ac
Δ = 02-4·(-36)·432
Δ = 62208
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{62208}=\sqrt{20736*3}=\sqrt{20736}*\sqrt{3}=144\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-144\sqrt{3}}{2*-36}=\frac{0-144\sqrt{3}}{-72} =-\frac{144\sqrt{3}}{-72} =-\frac{2\sqrt{3}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+144\sqrt{3}}{2*-36}=\frac{0+144\sqrt{3}}{-72} =\frac{144\sqrt{3}}{-72} =\frac{2\sqrt{3}}{-1} $
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