433(6x-3)+2=(2x-7)

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Solution for 433(6x-3)+2=(2x-7) equation: 



433(6x-3)+2=(2x-7)

We move all terms to the left:

433(6x-3)+2-((2x-7))=0

We multiply parentheses

2598x-((2x-7))-1299+2=0



We calculate terms in parentheses: -((2x-7)), so:

(2x-7)

We get rid of parentheses

2x-7

Back to the equation:

-(2x-7)



We add all the numbers together, and all the variables

2598x-(2x-7)-1297=0

We get rid of parentheses

2598x-2x+7-1297=0

We add all the numbers together, and all the variables

2596x-1290=0

We move all terms containing x to the left, all other terms to the right

2596x=1290

x=1290/2596

x=645/1298

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