433=2(-19x-20)+17

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Solution for 433=2(-19x-20)+17 equation: 



433=2(-19x-20)+17

We move all terms to the left:

433-(2(-19x-20)+17)=0



We calculate terms in parentheses: -(2(-19x-20)+17), so:

2(-19x-20)+17

We multiply parentheses

-38x-40+17

We add all the numbers together, and all the variables

-38x-23

Back to the equation:

-(-38x-23)



We get rid of parentheses

38x+23+433=0

We add all the numbers together, and all the variables

38x+456=0

We move all terms containing x to the left, all other terms to the right

38x=-456

x=-456/38

x=-12

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