435=107+3b+b

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Solution for 435=107+3b+b equation: 



435=107+3b+b

We move all terms to the left:

435-(107+3b+b)=0

We add all the numbers together, and all the variables

-(4b+107)+435=0

We get rid of parentheses

-4b-107+435=0

We add all the numbers together, and all the variables

-4b+328=0

We move all terms containing b to the left, all other terms to the right

-4b=-328

b=-328/-4

b=+82

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