43=3+5(-2b-4)

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Solution for 43=3+5(-2b-4) equation: 



43=3+5(-2b-4)

We move all terms to the left:

43-(3+5(-2b-4))=0



We calculate terms in parentheses: -(3+5(-2b-4)), so:

3+5(-2b-4)

determiningTheFunctionDomain
5(-2b-4)+3

We multiply parentheses

-10b-20+3

We add all the numbers together, and all the variables

-10b-17

Back to the equation:

-(-10b-17)



We get rid of parentheses

10b+17+43=0

We add all the numbers together, and all the variables

10b+60=0

We move all terms containing b to the left, all other terms to the right

10b=-60

b=-60/10

b=-6

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