44(3+c)+c=c+444(3+c)+c=c+4

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Solution for 44(3+c)+c=c+444(3+c)+c=c+4 equation:



44(3+c)+c=c+444(3+c)+c=c+4
We move all terms to the left:
44(3+c)+c-(c+444(3+c)+c)=0
We add all the numbers together, and all the variables
44(c+3)+c-(c+444(c+3)+c)=0
We add all the numbers together, and all the variables
c+44(c+3)-(c+444(c+3)+c)=0
We multiply parentheses
c+44c-(c+444(c+3)+c)+132=0
We calculate terms in parentheses: -(c+444(c+3)+c), so:
c+444(c+3)+c
We add all the numbers together, and all the variables
2c+444(c+3)
We multiply parentheses
2c+444c+1332
We add all the numbers together, and all the variables
446c+1332
Back to the equation:
-(446c+1332)
We add all the numbers together, and all the variables
45c-(446c+1332)+132=0
We get rid of parentheses
45c-446c-1332+132=0
We add all the numbers together, and all the variables
-401c-1200=0
We move all terms containing c to the left, all other terms to the right
-401c=1200
c=1200/-401
c=-2+398/401

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