44(3+c)+c=c+444(3+c)+c=c+4

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Solution for 44(3+c)+c=c+444(3+c)+c=c+4 equation: 



44(3+c)+c=c+444(3+c)+c=c+4

We move all terms to the left:

44(3+c)+c-(c+444(3+c)+c)=0

We add all the numbers together, and all the variables

44(c+3)+c-(c+444(c+3)+c)=0

We add all the numbers together, and all the variables

c+44(c+3)-(c+444(c+3)+c)=0

We multiply parentheses

c+44c-(c+444(c+3)+c)+132=0



We calculate terms in parentheses: -(c+444(c+3)+c), so:

c+444(c+3)+c

We add all the numbers together, and all the variables

2c+444(c+3)

We multiply parentheses

2c+444c+1332

We add all the numbers together, and all the variables

446c+1332

Back to the equation:

-(446c+1332)



We add all the numbers together, and all the variables

45c-(446c+1332)+132=0

We get rid of parentheses

45c-446c-1332+132=0

We add all the numbers together, and all the variables

-401c-1200=0

We move all terms containing c to the left, all other terms to the right

-401c=1200

c=1200/-401

c=-2+398/401

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