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44+(x+20)3x=180
We move all terms to the left:
44+(x+20)3x-(180)=0
We add all the numbers together, and all the variables
(x+20)3x-136=0
We multiply parentheses
3x^2+60x-136=0
a = 3; b = 60; c = -136;
Δ = b2-4ac
Δ = 602-4·3·(-136)
Δ = 5232
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5232}=\sqrt{16*327}=\sqrt{16}*\sqrt{327}=4\sqrt{327}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{327}}{2*3}=\frac{-60-4\sqrt{327}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{327}}{2*3}=\frac{-60+4\sqrt{327}}{6} $
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