44-(2c+3)=4(c+5)

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Solution for 44-(2c+3)=4(c+5) equation: 



44-(2c+3)=4(c+5)

We move all terms to the left:

44-(2c+3)-(4(c+5))=0

We get rid of parentheses

-2c-(4(c+5))-3+44=0



We calculate terms in parentheses: -(4(c+5)), so:

4(c+5)

We multiply parentheses

4c+20

Back to the equation:

-(4c+20)



We add all the numbers together, and all the variables

-2c-(4c+20)+41=0

We get rid of parentheses

-2c-4c-20+41=0

We add all the numbers together, and all the variables

-6c+21=0

We move all terms containing c to the left, all other terms to the right

-6c=-21

c=-21/-6

c=3+1/2

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