44-(3+4)=29(c+5)+c

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Solution for 44-(3+4)=29(c+5)+c equation: 



44-(3+4)=29(c+5)+c

We move all terms to the left:

44-(3+4)-(29(c+5)+c)=0

We add all the numbers together, and all the variables

-(29(c+5)+c)+44-7=0

We add all the numbers together, and all the variables

-(29(c+5)+c)+37=0



We calculate terms in parentheses: -(29(c+5)+c), so:

29(c+5)+c

We add all the numbers together, and all the variables

c+29(c+5)

We multiply parentheses

c+29c+145

We add all the numbers together, and all the variables

30c+145

Back to the equation:

-(30c+145)



We get rid of parentheses

-30c-145+37=0

We add all the numbers together, and all the variables

-30c-108=0

We move all terms containing c to the left, all other terms to the right

-30c=108

c=108/-30

c=-3+3/5

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