44-(3c+4)=4(c+60)+c

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Solution for 44-(3c+4)=4(c+60)+c equation: 



44-(3c+4)=4(c+60)+c

We move all terms to the left:

44-(3c+4)-(4(c+60)+c)=0

We get rid of parentheses

-3c-(4(c+60)+c)-4+44=0



We calculate terms in parentheses: -(4(c+60)+c), so:

4(c+60)+c

We add all the numbers together, and all the variables

c+4(c+60)

We multiply parentheses

c+4c+240

We add all the numbers together, and all the variables

5c+240

Back to the equation:

-(5c+240)



We add all the numbers together, and all the variables

-3c-(5c+240)+40=0

We get rid of parentheses

-3c-5c-240+40=0

We add all the numbers together, and all the variables

-8c-200=0

We move all terms containing c to the left, all other terms to the right

-8c=200

c=200/-8

c=-25

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