44-(3c+4)=4(c+60)+c

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Solution for 44-(3c+4)=4(c+60)+c equation:



44-(3c+4)=4(c+60)+c
We move all terms to the left:
44-(3c+4)-(4(c+60)+c)=0
We get rid of parentheses
-3c-(4(c+60)+c)-4+44=0
We calculate terms in parentheses: -(4(c+60)+c), so:
4(c+60)+c
We add all the numbers together, and all the variables
c+4(c+60)
We multiply parentheses
c+4c+240
We add all the numbers together, and all the variables
5c+240
Back to the equation:
-(5c+240)
We add all the numbers together, and all the variables
-3c-(5c+240)+40=0
We get rid of parentheses
-3c-5c-240+40=0
We add all the numbers together, and all the variables
-8c-200=0
We move all terms containing c to the left, all other terms to the right
-8c=200
c=200/-8
c=-25

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