44-(3c+4)=4(c-+6)+c

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Solution for 44-(3c+4)=4(c-+6)+c equation: 



44-(3c+4)=4(c-+6)+c

We move all terms to the left:

44-(3c+4)-(4(c-+6)+c)=0

We add all the numbers together, and all the variables

-(3c+4)-(4(+c)+c)+44=0

We get rid of parentheses

-3c-(4(+c)+c)-4+44=0



We calculate terms in parentheses: -(4(+c)+c), so:

4(+c)+c

We add all the numbers together, and all the variables

c+4(+c)

We multiply parentheses

c+4c

We add all the numbers together, and all the variables

5c

Back to the equation:

-(5c)



We add all the numbers together, and all the variables

-8c+40=0

We move all terms containing c to the left, all other terms to the right

-8c=-40

c=-40/-8

c=+5

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