44-(3c+4)=4(c-+6)+c

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Solution for 44-(3c+4)=4(c-+6)+c equation:



44-(3c+4)=4(c-+6)+c
We move all terms to the left:
44-(3c+4)-(4(c-+6)+c)=0
We add all the numbers together, and all the variables
-(3c+4)-(4(+c)+c)+44=0
We get rid of parentheses
-3c-(4(+c)+c)-4+44=0
We calculate terms in parentheses: -(4(+c)+c), so:
4(+c)+c
We add all the numbers together, and all the variables
c+4(+c)
We multiply parentheses
c+4c
We add all the numbers together, and all the variables
5c
Back to the equation:
-(5c)
We add all the numbers together, and all the variables
-8c+40=0
We move all terms containing c to the left, all other terms to the right
-8c=-40
c=-40/-8
c=+5

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