44-(3c+4)=4(c-6)+6

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Solution for 44-(3c+4)=4(c-6)+6 equation:



44-(3c+4)=4(c-6)+6
We move all terms to the left:
44-(3c+4)-(4(c-6)+6)=0
We get rid of parentheses
-3c-(4(c-6)+6)-4+44=0
We calculate terms in parentheses: -(4(c-6)+6), so:
4(c-6)+6
We multiply parentheses
4c-24+6
We add all the numbers together, and all the variables
4c-18
Back to the equation:
-(4c-18)
We add all the numbers together, and all the variables
-3c-(4c-18)+40=0
We get rid of parentheses
-3c-4c+18+40=0
We add all the numbers together, and all the variables
-7c+58=0
We move all terms containing c to the left, all other terms to the right
-7c=-58
c=-58/-7
c=8+2/7

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