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44-(3x+4)=2(x+5)+x
We move all terms to the left:
44-(3x+4)-(2(x+5)+x)=0
We get rid of parentheses
-3x-(2(x+5)+x)-4+44=0
We calculate terms in parentheses: -(2(x+5)+x), so:We add all the numbers together, and all the variables
2(x+5)+x
We add all the numbers together, and all the variables
x+2(x+5)
We multiply parentheses
x+2x+10
We add all the numbers together, and all the variables
3x+10
Back to the equation:
-(3x+10)
-3x-(3x+10)+40=0
We get rid of parentheses
-3x-3x-10+40=0
We add all the numbers together, and all the variables
-6x+30=0
We move all terms containing x to the left, all other terms to the right
-6x=-30
x=-30/-6
x=+5
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