44=(2x+1)(x+3)/2

Solution for 44=(2x+1)(x+3)/2 equation:

44=(2x+1)(x+3)/2

We move all terms to the left:

44-((2x+1)(x+3)/2)=0

We multiply parentheses ..

-((+2x^2+6x+x+3)/2)+44=0

We multiply all the terms by the denominator


-((+2x^2+6x+x+3)+44*2)=0


We calculate terms in parentheses: -((+2x^2+6x+x+3)+44*2), so:

(+2x^2+6x+x+3)+44*2

We add all the numbers together, and all the variables

(+2x^2+6x+x+3)+88

We get rid of parentheses

2x^2+6x+x+3+88

We add all the numbers together, and all the variables

2x^2+7x+91

Back to the equation:

-(2x^2+7x+91)


We get rid of parentheses

-2x^2-7x-91=0

a = -2; b = -7; c = -91;
Δ = b2-4ac
Δ = -72-4·(-2)·(-91)
Δ = -679
Delta is less than zero, so there is no solution for the equation