44=(2x+1)(x+3)/2

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Solution for 44=(2x+1)(x+3)/2 equation:



44=(2x+1)(x+3)/2
We move all terms to the left:
44-((2x+1)(x+3)/2)=0
We multiply parentheses ..
-((+2x^2+6x+x+3)/2)+44=0
We multiply all the terms by the denominator
-((+2x^2+6x+x+3)+44*2)=0
We calculate terms in parentheses: -((+2x^2+6x+x+3)+44*2), so:
(+2x^2+6x+x+3)+44*2
We add all the numbers together, and all the variables
(+2x^2+6x+x+3)+88
We get rid of parentheses
2x^2+6x+x+3+88
We add all the numbers together, and all the variables
2x^2+7x+91
Back to the equation:
-(2x^2+7x+91)
We get rid of parentheses
-2x^2-7x-91=0
a = -2; b = -7; c = -91;
Δ = b2-4ac
Δ = -72-4·(-2)·(-91)
Δ = -679
Delta is less than zero, so there is no solution for the equation

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