44=2(3n+3)+2(2n-1)

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Solution for 44=2(3n+3)+2(2n-1) equation: 



44=2(3n+3)+2(2n-1)

We move all terms to the left:

44-(2(3n+3)+2(2n-1))=0



We calculate terms in parentheses: -(2(3n+3)+2(2n-1)), so:

2(3n+3)+2(2n-1)

We multiply parentheses

6n+4n+6-2

We add all the numbers together, and all the variables

10n+4

Back to the equation:

-(10n+4)



We get rid of parentheses

-10n-4+44=0

We add all the numbers together, and all the variables

-10n+40=0

We move all terms containing n to the left, all other terms to the right

-10n=-40

n=-40/-10

n=+4

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