44=2(n+12)-18

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Solution for 44=2(n+12)-18 equation: 



44=2(n+12)-18

We move all terms to the left:

44-(2(n+12)-18)=0



We calculate terms in parentheses: -(2(n+12)-18), so:

2(n+12)-18

We multiply parentheses

2n+24-18

We add all the numbers together, and all the variables

2n+6

Back to the equation:

-(2n+6)



We get rid of parentheses

-2n-6+44=0

We add all the numbers together, and all the variables

-2n+38=0

We move all terms containing n to the left, all other terms to the right

-2n=-38

n=-38/-2

n=+19

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