44=4(2+z)+8

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Solution for 44=4(2+z)+8 equation:



44=4(2+z)+8
We move all terms to the left:
44-(4(2+z)+8)=0
We add all the numbers together, and all the variables
-(4(z+2)+8)+44=0
We calculate terms in parentheses: -(4(z+2)+8), so:
4(z+2)+8
We multiply parentheses
4z+8+8
We add all the numbers together, and all the variables
4z+16
Back to the equation:
-(4z+16)
We get rid of parentheses
-4z-16+44=0
We add all the numbers together, and all the variables
-4z+28=0
We move all terms containing z to the left, all other terms to the right
-4z=-28
z=-28/-4
z=+7

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