44=4(s+3)s=-7s=8

Solution for 44=4(s+3)s=-7s=8 equation:

44=4(s+3)s=-7s=8

We move all terms to the left:

44-(4(s+3)s)=0


We calculate terms in parentheses: -(4(s+3)s), so:

4(s+3)s

We multiply parentheses

4s^2+12s

Back to the equation:

-(4s^2+12s)


We get rid of parentheses

-4s^2-12s+44=0

a = -4; b = -12; c = +44;
Δ = b2-4ac
Δ = -122-4·(-4)·44
Δ = 848
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{848}=\sqrt{16*53}=\sqrt{16}*\sqrt{53}=4\sqrt{53}$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4\sqrt{53}}{2*-4}=\frac{12-4\sqrt{53}}{-8}
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4\sqrt{53}}{2*-4}=\frac{12+4\sqrt{53}}{-8}
$