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44=u2
We move all terms to the left:
44-(u2)=0
We add all the numbers together, and all the variables
-1u^2+44=0
a = -1; b = 0; c = +44;
Δ = b2-4ac
Δ = 02-4·(-1)·44
Δ = 176
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{176}=\sqrt{16*11}=\sqrt{16}*\sqrt{11}=4\sqrt{11}$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{11}}{2*-1}=\frac{0-4\sqrt{11}}{-2} =-\frac{4\sqrt{11}}{-2} =-\frac{2\sqrt{11}}{-1} $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{11}}{2*-1}=\frac{0+4\sqrt{11}}{-2} =\frac{4\sqrt{11}}{-2} =\frac{2\sqrt{11}}{-1} $
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