44=v2-4

Solution for 44=v2-4 equation:

44=v2-4

We move all terms to the left:

44-(v2-4)=0

We add all the numbers together, and all the variables

-(+v^2-4)+44=0

We get rid of parentheses

-v^2+4+44=0

We add all the numbers together, and all the variables

-1v^2+48=0

a = -1; b = 0; c = +48;
Δ = b2-4ac
Δ = 02-4·(-1)·48
Δ = 192
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{192}=\sqrt{64*3}=\sqrt{64}*\sqrt{3}=8\sqrt{3}$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{3}}{2*-1}=\frac{0-8\sqrt{3}}{-2}
=-\frac{8\sqrt{3}}{-2}
=-\frac{4\sqrt{3}}{-1}
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{3}}{2*-1}=\frac{0+8\sqrt{3}}{-2}
=\frac{8\sqrt{3}}{-2}
=\frac{4\sqrt{3}}{-1}
$