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44=x(3-2x)
We move all terms to the left:
44-(x(3-2x))=0
We add all the numbers together, and all the variables
-(x(-2x+3))+44=0
We calculate terms in parentheses: -(x(-2x+3)), so:We get rid of parentheses
x(-2x+3)
We multiply parentheses
-2x^2+3x
Back to the equation:
-(-2x^2+3x)
2x^2-3x+44=0
a = 2; b = -3; c = +44;
Δ = b2-4ac
Δ = -32-4·2·44
Δ = -343
Delta is less than zero, so there is no solution for the equation
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