45(2m-1)(m-5)=0

Solution for 45(2m-1)(m-5)=0 equation:

45(2m-1)(m-5)=0

We multiply parentheses ..

45(+2m^2-10m-1m+5)=0

We multiply parentheses

90m^2-450m-45m+225=0

We add all the numbers together, and all the variables

90m^2-495m+225=0

a = 90; b = -495; c = +225;
Δ = b2-4ac
Δ = -4952-4·90·225
Δ = 164025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{164025}=405$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-495)-405}{2*90}=\frac{90}{180}
=1/2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-495)+405}{2*90}=\frac{900}{180}
=5
$