45(b-1)+10=5(9b-7)

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Solution for 45(b-1)+10=5(9b-7) equation: 



45(b-1)+10=5(9b-7)

We move all terms to the left:

45(b-1)+10-(5(9b-7))=0

We multiply parentheses

45b-(5(9b-7))-45+10=0



We calculate terms in parentheses: -(5(9b-7)), so:

5(9b-7)

We multiply parentheses

45b-35

Back to the equation:

-(45b-35)



We add all the numbers together, and all the variables

45b-(45b-35)-35=0

We get rid of parentheses

45b-45b+35-35=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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