45(x-1)-40(3x+1)=12(x-12)

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Solution for 45(x-1)-40(3x+1)=12(x-12) equation: 



45(x-1)-40(3x+1)=12(x-12)

We move all terms to the left:

45(x-1)-40(3x+1)-(12(x-12))=0

We multiply parentheses

45x-120x-(12(x-12))-45-40=0



We calculate terms in parentheses: -(12(x-12)), so:

12(x-12)

We multiply parentheses

12x-144

Back to the equation:

-(12x-144)



We add all the numbers together, and all the variables

-75x-(12x-144)-85=0

We get rid of parentheses

-75x-12x+144-85=0

We add all the numbers together, and all the variables

-87x+59=0

We move all terms containing x to the left, all other terms to the right

-87x=-59

x=-59/-87

x=59/87

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