45-(2c+3)=4(c+7)+7

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Solution for 45-(2c+3)=4(c+7)+7 equation: 



45-(2c+3)=4(c+7)+7

We move all terms to the left:

45-(2c+3)-(4(c+7)+7)=0

We get rid of parentheses

-2c-(4(c+7)+7)-3+45=0



We calculate terms in parentheses: -(4(c+7)+7), so:

4(c+7)+7

We multiply parentheses

4c+28+7

We add all the numbers together, and all the variables

4c+35

Back to the equation:

-(4c+35)



We add all the numbers together, and all the variables

-2c-(4c+35)+42=0

We get rid of parentheses

-2c-4c-35+42=0

We add all the numbers together, and all the variables

-6c+7=0

We move all terms containing c to the left, all other terms to the right

-6c=-7

c=-7/-6

c=1+1/6

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