45-(2c+3)=4(c+7)=c

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Solution for 45-(2c+3)=4(c+7)=c equation: 



45-(2c+3)=4(c+7)=c

We move all terms to the left:

45-(2c+3)-(4(c+7))=0

We get rid of parentheses

-2c-(4(c+7))-3+45=0



We calculate terms in parentheses: -(4(c+7)), so:

4(c+7)

We multiply parentheses

4c+28

Back to the equation:

-(4c+28)



We add all the numbers together, and all the variables

-2c-(4c+28)+42=0

We get rid of parentheses

-2c-4c-28+42=0

We add all the numbers together, and all the variables

-6c+14=0

We move all terms containing c to the left, all other terms to the right

-6c=-14

c=-14/-6

c=2+1/3

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