45-(2c+4)=4(c+7)+c

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Solution for 45-(2c+4)=4(c+7)+c equation:



45-(2c+4)=4(c+7)+c
We move all terms to the left:
45-(2c+4)-(4(c+7)+c)=0
We get rid of parentheses
-2c-(4(c+7)+c)-4+45=0
We calculate terms in parentheses: -(4(c+7)+c), so:
4(c+7)+c
We add all the numbers together, and all the variables
c+4(c+7)
We multiply parentheses
c+4c+28
We add all the numbers together, and all the variables
5c+28
Back to the equation:
-(5c+28)
We add all the numbers together, and all the variables
-2c-(5c+28)+41=0
We get rid of parentheses
-2c-5c-28+41=0
We add all the numbers together, and all the variables
-7c+13=0
We move all terms containing c to the left, all other terms to the right
-7c=-13
c=-13/-7
c=1+6/7

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